NECO Chemistry Questions and Answers 2024 OBJ & Theory Update

Filed in Education by on February 1, 2022

– NECO Chemistry Questions and Answers –

In this article, I will be showing you past NECO Mathematics objective and theory random repeated questions and answers for free. Stay focused and read through.

The National Examinations Council is an examination body in Nigeria that conducts the Senior Secondary Certificate Examination and the General Certificate in Education in June/July and December/January respectively.

NECO Chemistry Questions and Answers

Take note of these objective answers below:

CHEMISTRY OBJ :
1-10 DCBBCBBEDC
11-20 CADECEBBDC
21-30 EEBABDADBE
31-40 AECCACDDDC
41-50 DABABCBBCA
51-60 CBBAABCADE
1ai)
A mixture contains two or more constituents which can easily be separated by physical methods
1aii)
magnesium trioxonitrate(v) = Mg(NO3)2
molar mass of Mg(NO3)2
=(1*24) + 2 (14*1 + 16*3)
=24 + 2 (14 + 48)
=24 + 28 + 96 = 148g/mol
% of nitrogen = 2*24*100/148
% of nitrogen = 48*100/148
% of nitrogen = 4800/148
% of nitrogen = 32.43%
1aiii)
i)calcium oxide (CaO)
ii)calcium chloride (CaCl2)
1bi)
CnH2n+1OH
1bii)
hydrolysation
1biii)
i)displacement reaction
ii)double decomposition reaction
iii)decomposition reaction
iv)catalytic reaction
v)reversible reaction
1biv)
i)endothermic heat change
ii)exothermic heat change
1ci)
i)methyl orange
ii)phenolphthalein
iii)litmus
1cii)
NH4Cl+Ca(OH)2—–>CaCl2+2NH3+2H2O
1ciii)
it is collected by upward delivery
1civ)
mass of gas = 1.58*22.4 = 35.392
vapour density = 35.392/1
relative molecular mass= V . D * 2
=35.392*2
relative molecular mass= 70.784
==================================
2ai)
i)carbon monoxide and hydrogen
ii)carbon monoxide,carbon dioxide,hydrogen and nitrogen
2aii)
i)colloids is an intermediate between true solution and a suspension
ii)condensation is the process by which water vapour in the air is changed to liquid water
2bi)
CaC03+2HCl—–>CaCl2+H2O+CO2
2bii)
i)it is used in fire extinguishers
ii)it is used in the manufacturing of mineral water
iii)carbon(iv)oxide is used as a coolant in nuclear reactors
2biii)
i)Cr2O7^-2
=2Cr + C-2*7) = -2
2Cr – 14 = -2
2Cr = -2 + 14
2Cr/2 = 12/2
Cr = 6
ii)Cr2{SO4}3
2Cr + 3 (-2*1 + -2*4) = 0
2Cr + 3 (-2 – 8) = 0
2Cr + 3 (-10) = 0
2Cr – 30 = 0
2Cr/2 = 30/2
Cr = 15
2ci)
vulcanization is a chemical process of converting netural rubber or related polymers into more durable materials through the addition of sulphur or other equivalent curatives or accelerators
2cii)
Time Taken(t) for 6.35g of copper(ii)tetraoxosulphate
solution
Cu^2^+ + 2c ——->Cu
Q = 2*63.5*95600
Q = 12255500
Q = 1t
12255500/10 = 10*t/10
t = 1225550/60 = 204258.3
2ciii)
Latex
==================================
3ai)
electrolytic cell is a cell that consist of a container of electrolyte with two electrodes connected to a suitable direct current supply
3aii)
i)daniel cell
ii)Leclanché cell
4aiii)
i)copper
ii)tin
3aiv)
action of dilute acide on zinc
4av)
Zn+2HCl——>ZnCl+H2
3bi)
i)dinitrogen(i)oxide(N2O)
ii)nitrogen(v)oxide(N2O5)
iii)nitrogen(iv)oxide(NO2)
3bii)
charle’s law states that the volume of a fixed mass of gas varies directly with the absolute(kelvin)temperature provided the pressure remains constant.
3biii)
P1 V1 = P2 V2
given that
P1 = 900mmHg
P2 = 750mmHg
V1 = 300cm^3
V2 = ?
V2 = P1V1/P2
V2 = 900*300/750
V2 = 270000/750
V2 = 360cm^3
3biv)
% composition carbon
= 12/(12*6) + (1*6) *100%
= 12/72+6 *100
= 12/78 * 100% = 1200/78%
%composition of carbon = 15.38%
3c)
TABULATE -THERMOPLASTS-
i)it melts when heat is applied to it
ii)highly recycled
-THERMOSETS-
i)does not melt when heat is applied
ii)cannot be recycled
==================================
4ai)
ionization energy deals with electron loss while electron loss while electron afinity deals with electron gain
4aii)
i)they are used to dry gases
ii)they are used to recover valuable vapours from industrial effluents and refine petroleum
4bi)
TABULATE-RHOMBIC SULPHUR-
i)bright yellow in colour
ii)it is octohedral in shape
-MONOCLINIC SULPHUR-
i)amber in colour
ii)it is needle like in shape
4bii)
oxygen = 60%
sodium = 40%
oxygen 60/16
3.75/1.74 = 2
sodium 40/23
1.74/1.74 = 1
the emperical formula is NaO2
4biii)
sodium(iv)oxide
4ci)
i)x is hydrophobic region
ii)y is hydrophilic religion
4cii)
i)for laundry purpose
ii)for fuel
4ciii)
i)the distance of outermost electron from the nucleus
ii)the size of the positive nuclear charge
iii)the screening effect of inner electrons
4civ)
period law states that the properties of the elements are a period function of their atomic number
4di)
n—pentane—–>n—butane—–>2—methylbutane—2,2—dimethylpropane
4dii)
i)glucose
ii)galactose
==================================
Completed. enjoy.

CHEMISTRY OBJ :
1-10 DCBBCBBEDC
11-20 CADECEBBDC
21-30 EEBABDADBE
31-40 AECCACDDDC
41-50 DABABCBBCA
51-60 CBBAABCADE
1ai) A mixture contains two or more constituents which can easily be seperated by physical methods 1aii) magnesium trioxonitrate(v) = Mg(NO3)2 molar mass of Mg(NO3)2 =(1*24) + 2 (14*1 + 16*3) =24 + 2 (14 + 48) =24 + 28 + 96 = 148g/mol % of nitrogen = 2*24*100/148 % of nitrogen = 48*100/148 % of nitrogen = 4800/148 % of nitrogen = 32.43% 1aiii) i)calcium oxide (CaO) ii)calcium choride (CaCl2)
1bi) CnH2n+1OH 1bii) hydrolysation 1biii) i)displacement reaction ii)double decomposition reaction iii)decomposition reaction iv)catalytic reaction v)reversible reaction 1biv) i)endothermic heat change ii)exothermic heat change
1ci) i)methyl orange ii)phenolphthalein iii)litmus 1cii) NH4Cl+Ca(OH)2—–>CaCl2+2NH3+2H2O 1ciii) it is collected by upward delivery 1civ) mass of gas = 1.58*22.4 = 35.392 vapour density = 35.392/1 relative molecular mass= V . D * 2 =35.392*2 relative molecular mass= 70.784 ==================================
2ai) i)carbon monoxide and hydrogen ii)carbon monoxide,carbon dioxide, hydrogen and nitrogen 5aii) i)colloids is an intermediate between true solution and a suspension ii)condensation is the process by which water vapour in the air is changed to liquid water
2bi) CaC03+2HCl—–>CaCl2+H2O+CO2 5bii) i)it is used in fire extinguishers ii)it is used in the manufacturing of mineral water iii) carbon(iv)oxide is used as a coolant in nuclear reactors 5biii) i)Cr2O7^-2 =2Cr + C-2*7) = -2 2Cr – 14 = -2 2Cr = -2 + 14 2Cr/2 = 12/2 Cr = 6 ii)Cr2{SO4}3 2Cr + 3 (-2*1 + -2*4) = 0 2Cr + 3 (-2 – 8) = 0 2Cr + 3 (-10) = 0 2Cr – 30 = 0 2Cr/2 = 30/2 Cr = 15
2ci) vulcanization is a chemical process of converting netural rubber or related polymers into more durable materials through the addition of sulphur or other equivalent curatives or accelerators 5cii) Time Taken(t) for 6.35g of copper(ii)tetraoxosulphate solution Cu^2^+ + 2c ——->Cu Q = 2*63.5*95600 Q = 12255500 Q = 1t 12255500/10 = 10*t/10 t = 1225550/60 = 204258.3 5ciii) Latex ==================================
3ai) electrolytic cell is a cell that consist of a container of electrolyte with two electrodes connected to a suitable direct current supply 4aii) i)daniel cell ii)Leclanché cell 4aiii) i)copper ii)tin 4aiv) action of dilute acide on zinc 4av) Zn+2HCl——>ZnCl+H2
3bi) i)dinitrogen(i)oxide(N2O) ii)nitrogen(v)oxide(N2O5) iii)nitrogen(iv)oxide(NO2) 4bii) charle’s law states that the volume of a fixed mass of gas varies directly with the absolute(kelvin)temperature provided the pressure remains constant. 4biii) P1 V1 = P2 V2 given that P1 = 900mmHg P2 = 750mmHg V1 = 300cm^3 V2 = ? V2 = P1V1/P2 V2 = 900*300/750 V2 = 270000/750 V2 = 360cm^3 4biv) % composition carbon = 12/(12*6) + (1*6) *100% = 12/72+6 *100 = 12/78 * 100% = 1200/78% %composition of carbon = 15.38%
3c) TABULATE -THERMOPLASTS- i)it melts when heat is applied to it ii)highly recycled
-THERMOSETS- i)does not melt when heat is applied ii)cannot be recycled ==================================
4ai) ionization energy deals with electron loss while electron loss while electron afinity deals with electron gain 2aii) i)they are used to dry gases ii)they are used to recover valuable vapours from industrial effluents and refine petroleum
4bi) TABULATE -RHOMBIC SULPHUR- i)bright yellow in colour ii)it is octohedral in shape -MONOCLINIC SULPHUR- i)amber in colour ii)it is needle like in shape 2bii) oxygen = 60% sodium = 40% oxygen 60/16 3.75/1.74 = 2 sodium 40/23 1.74/1.74 = 1 the emperical formula is NaO2 2biii) sodium(iv)oxide
4ci) i)x is hydrophobic region ii)y is hydrophilic religion 2cii) i)for laundry purpose ii)for fuel 2ciii) i)the distance of outermost electron from the nucleus ii)the size of the positive nuclear charge iii)the screening effect of inner electrons 2civ) period law states that the properties of the elements are a period function of their atomic number
4di) n—pentane—–>n—butane—–>2—methylbutane—2,2—dimethylpropane 2dii) i)glucose ii)galactose ================================== Completed. enjoy.

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