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WAEC Physics Practical Questions 2019 and Answers is Out for Free

Filed in Exam, WAEC News by on March 14, 2019 4 Comments

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WAEC Physics Practical Questions 2019 and Answers is Out for Free.

WAEC | WAEC Physics Practical Questions 2019… This page contains list of Physics labouratory apparatus that will be used for the May/June 2018 Physics practical examination.

WAEC Physics Practical Questions WAEC Physics Practical Questions 2019

The West African Examinations Council (WAEC) is an examination board that conducts the West African Senior School Certificate Examination, for University and Jamb entry examination in West Africa countries. … In a year, over three million candidates registered for the exams coordinated by WAEC.

The Waec Physics practical Alternative A will take place on Wednesday, 4th April, 2018 from 08:30am to 11:15am (1st Set) and 11:40am to 02:25pm (2nd Set).

Physics Practical Alternative B will be written on Friday, 6th April, 2018 from 08:30am to 11:15am (1st Set) and 11:40am to 02:25pm (2nd Set)

The physics practical is usually divided into 3 questions (comprising of Mechanics, Waves and Electricity) with a few other general knowledge calculations.

WAEC Physics Practical Answers.

(1)
TABULATE:
i:1,2,3,4,5,
L(cm):80.00,70.00,60.00,50.00,40.00
t1(s):17.87,16.22,16.09,14.08,13.28
t2(2):17.56,16.46,15.09,14.77,13.36
t(s)mean:17.715,16.340,15.590,14.425,13.320
T(t/10)s:1.7715,1.6340,1.5590,1.4425,1.3320
LogT(s):0.2483,0.2133,0.1928,0.1591,0.1212
Log L(cm):1.9031,1.8451,1.7782,1.6990,1.6021
Log T*10^-2(s):24.83,21.33,19.28,15.91,12.12
Log L*10^-1(cm):19.031,18.451,17.782,16.990,16.021
SLOPE(s)=(LogT2*10^-2 – LogT1*10^-2)(/Log L2 *10^-1 – LogL1*10^-1)
=(21.33-12.12(s))*10^-2/(18.50-16.02(cm)*10^-1)
=3.714*10^-1
=0.3714cm^-1

(1axi)
(i) I ensured supports of pendula were rigid
(ii) I avoided parallax error on the meter rule
(1bi)
Simple harmonic motion is the motion of a body whose acceleration is always direct towards a fixed point and is proportional to the displacement from the fixed points
(1bii)
T=1.2secs
Log 1.2=0.079
0079 shown on graph with corresponding Log L read L correctly determined
==========================================
(3a)
TABULATE:
x(cm):10,20,30,40,50,60
V(v):0.65,0.75,1.00,1.20,1.45,1.55
I(A):0.20,0.30,0.35,0.40,0.45,0.55
LogV(v):-0.187,-0.125,0.000,0.079,0.161,0.190
LogI(ohm):-0.699,-0.523,-0.456,-0.396,-0.391,-0.360
SLOPE(s):=( LogI2-LOgI1)/(LogV2-LogV1)
=-0.2-(-0.7)/0.3-(-0.2)
=0.5/0.5
=1AV^-1
(3axi)
(i) I ensured neat and tight terminals
(ii) I opened the key when reading was taken
(3bi)
(i)The brightness of the bulb increases
(ii) The voltage and current through the bulb increases
(3bii)
(i) diode
(ii) transistor

This page will be updated with the detailed table of values plus calculations associated with the WAEC physics practical for candidates.

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Comments (4)

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  1. Chima says:

    Please update me on other subjects

  2. Chima says:

    I need literature in English pls

  3. don says:

    thanks for this.

  4. Chima says:

    I need all papers, please update me. My number 08030826854

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