NECO Physics 2022 Questions and Answers Latest Update Here

Filed in Education by on February 1, 2022

NECO Physics 2020 Questions: NECO Physics Answers and Questions is now out and available online. This page contains a list of Physics Questions that will be asked for the June/July 2018 Physics Examination. See more below;

The National Examinations Council (also known as NECO) is an examination body in Nigeria that conducts the Senior Secondary Certificate Examination and the General Certificate in Education. NECO was created by former Head of State Abdulsalami Abubakar in April 1999. It was the first Federal organization to offer subsidized registration to academic candidates in Nigeria.

NECO Physics 2020 Questions

PHYSICS OBJ:
1CEABCBAABB
11DCCBCBCCAE
21BECDDBEDDE
31DBAEADBABA
41CBDCBBBDCB
51CEDDCBAEAA

PART I – ANSWER 6
1ai)
i)propellant
ii)nozzle
1aii)
i)used for communication
ii)used for access geographically dispersed terrains and uneven topography that characterise the nations landscappe

1b)
Given: Object distance for eyepiece, U=3.0cm
Final image distance, V=?
Focal length of eyepiece, F=5.0cm
using the mirror/lens formular
1/f=1/u+1/v
1/5=1/3+1/v
multiplying through with 15v(1.cm)
3v=5v+15
3v-5v=15
-2v=-15/2
V=7.5cm
the final image is virtual and 7.5cm from the eyepiece on the same side of the eyepiece as the object

2)
Given Radius, r=25m
linear velocity, v=20m|s
centripetal acceleration,a=?
Using:
a=V^2/r2
a=20^2/25
a=16m|s^2

6a)
A wave front is the locus of points characterized by propagation of position of the same phase: a propagation of a line in 1D, a curve in 2D or a surface for a wave in 3D. In other words a line or surface in the path of an advancing wave on which all the particles are vibrating in phase is called a wave front.

6b)
i)plane wave front
ii)spherical wave front

7)
Pupil- Regulates the amount of light entering the eye
Shutter-admits or shuts off light from the film of the camera
Screen-used to focus light from a near object in front of the pinhold camere

9a)
i)over charging (for secondary cell)
ii)self discharge (for primary cell)

9b)
self discharge- a primary cell lose a considerable percentage of their charge when stored at room temperature, this is due to non-current-producing “side” chemical reactions that occur within the cell even when no load is applied

10)
i)fusion is more easily achieved with lightest elements such as hydrogen
ii)the raw materials required for fussion are more cheaply and readily available
iii)fusion process produce less dangerous by product

PART II – ANSWER 4
12ai)
Newton’s second law of motion states that the rate of change of momentum is proportional to the impressed fotvr and takes place in the direction of the force
12aii)
i)a swinging pendulum
ii)The motion of the balance wheel of a watch

12bi)
Resultant force is that single force which acting alone will have the same effect in magnitude and direction as two or more forces acting together
12bii)
Equilbrum force is that single force which will balance all the other forces taken together. It is equal in magnitude buy opposite in direction to the resultant force

12ci)
Resultant,Force,F=sqr4^2+3^2
F=sqr16+9
Fsqr25=5N
12cii)
using F=m(v-u)/t
5=5.5(v-2)/(5*60)
5*60*5=5.5(v-2)
=5.5(v-2)=1500
V-2=272.7
V=272.7+2
V=274.7m|s
final velocity of body = 274.7m|s

13ai)
i)Solar energy is for providing a cheap and clean source of hot water supply.
ii)Solar energy provides electricity supply
13aii)
Renewable energy are those that can be replaced as they are used up. They can be continually replenished as they are exploited and utilized while Non-Renewable energy are those that cannot be replenished as they are used up

13b)
The principle of conservation of linear momentum us also utilized in the propulsion of jet aircraft. Gases are burnt within the combustion chambers of the engine. As jets of hot gases are expelled downwards through the tail nozzle at very high speeds from the aircraft, an equal and opposite momentum is given to the rocket or aircraft which then moves

13c)
Given: mass, m=0.2kg
heat lost,it=4200J
intial temperature cost r= 100’C
final temperature cost=?
S. It . c of water, C10=4200J/kg/k
using:
heat lost= M10, C10 (cost-tf)
400=0.2*4200*(100-costf)
=4200/0.2*4200
100-costF=5
100-5=costf
=cost=100-5
costf=95’C
final temperature=95’C

14ai)
A transverse wave is one which travels perpendicularly to the direction of the vibration producing the wave.
14aii)
i)Light Wave do not need a material medium for preparation, but sound wave does
ii)Light wave cannot be plane polarised but sound wave can

14b)
Given Y= 4sin (100×22/7xt/2 + 0.5x)
Comparing with
Y = A sin (2xPIxft + 2pi/pi x) Note : {the PI is the 22/7}
14bi)
2 x 3.142/0.5 = 12.56cm
Hence Wave length is 12.56
14bii)
Also 1000PI/wave length = 2PI F
= 1000PI/12.56 = 500/12.56
= 39.8Hz
14biii)
Speed (v) = F x Wave length
= V = F x Wave Length
V = 500/12.56 x 12.56‎
= 500cm/s
Conversation to M = 500/100
= 5m/s‎

15a)
Coulomb’s Law state that the magnitude of the electrostatic force between two point charges is directly proportional to the product of the magnitudes of the charges and inversely proportional to the square of the distance between them.

15bi)
diagram
R1
R2
R3
I<-V
15bii)
let equivalent resistance be R
1/R=1/R1+1/R2+1/R3
1/R=R2,R3+R1,R3+R1,R2/R1,R2,R3
R=R1,R2,R3/R1,R2,+R2,R3+R1,R3

15C)
Given; R=20n,C=4HF,F=50H2,TI=3.14
z=sqr R^2+(1/2TiFc)
z=sqr200^2+(1/2*314*50*4*10^-6)
z=sqr200^2+796.178^2
z=sqr40000+633900
z=sqr673900
z=821n

Theory Questions

1. (a) A student makes a model of an atom. The model contains 24 electrons, 25 protons and 26 neutrons. Some of these particles are inside a nucleus at the centre of the model.
(i) Determine the nucleon number (mass number) of the atom.
(ii) Explain why the model represents a charged atom.
(iii) The student makes a new model of a different isotope of the same element. Describe the nucleus of this new model.

Ans: 1 (a)
(i) 51 B1
(ii) more protons than electrons or different number of protons and electrons positive and negative do not cancel.
(iii) 25 protons. a different number of neutrons.

2. Fig. 1.1 shows the distance-time graph for two cyclists A and B. They start a 500 m race together but finish the race at different times.

NECO Physics 2018 Questions

(a) Use Fig. 1.1 to determine
(i) the distance between A and B at time t = 20s,
(ii) the difference in the time taken by A and B for the race.

(b) Cyclist C starts the race at the same time as A and B and covers the first 200m of the race at a constant speed of 5.0 m/s. He then accelerates and finishes the race at t = 60s.
(i) On Fig. 1.1, draw the distance-time graph for cyclist C.
(ii) Calculate the average speed of cyclist C for the whole race.

Ans: (a) (i) 60 m
(ii) 12s
(b) (i) straight line from origin to 200 m at 40s any line straight or curved from (40,200) to (60,500)
(ii) s = d/t or 500/60 = 8.3m/s.

OBJ Sample Questions

If a satellite travels at a constant speed round the earth in a circular orbit,

1. Which of the quantities in the list below are scalars.
(a) acceleration (b) force (c) mass (e) speed.

2. The velocity of the satellite changes, but its speed is constant. State what is meant by velocity…………………….

3. Explain why the velocity changes……………………………

4. Explain what makes this satellite move in an orbit that is circular.

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