# WAEC GCE Further Mathematics Questions 2019 | Check OBJ and Theory Answers Here

**WAEC GCE Further Mathematics Questions 2019 | Check OBJ and Theory Answers Here.**

Further Mathematics, Further Mathematics WAECQuestions 2019 | In this article, I will be showing you past Further Mathematics objective and theory random repeatedquestionsfor free. You will also understand howWAEC FurtherMathematics questions are set and many other examination guides. Stay focus and read through.

The West African Examinations Council (WAEC) is an examination board that conducts the West African Senior School Certificate Examination, for University and Jamb entry examination in West Africa countries. … In a year, over three million candidates registered for the exams coordinated by WAEC.

**WAEC GCE Further Mathematics Questions 2019**

**Keep refreshing this page as update will be made in jiffy**

FURTHER MATHS OBJ:

1-10: BBADDBABDA

11-20: ACBABDBDAB

21-30: BDDBCBACCD

31-40: ACBDACDBAB

1a)

8m + 2³m = 1/4

2²m + 2²m = 2-²

4³m = 2-²

Equate the base

6m = – 2

m = -2/4 = -1/3

1b)

log15 base 4 = x

x = log15 base/log4 base 10 = 1.1761/0.6020

= 1.9536

therefore x approximately 1.954

========

2a)

(-2) = m(-2)² + n(-2)+2=0

4m-2n = – – – – – – – – (1)

F(1) = m(1)²+n(1)+2=3

m+n+2=3

m+n=3-2

m+n=1 – – – – – – – – – – – -(2)

X Equate (2) by 4

4m+4n=4 – – – – – – – – – – (3)

4m-2n= -2

-4m+4n=4/-6n = – 6

n=1

============

4)

Given y= 5/x² + 3

Y = 5(x² +3)-1

dy/dx = anxn-1

y = 5(x² + 3)-1

dy = 5(-1) (x2 +3)-1^1

dy/dx = 10x (x² + 3)-²

dy/dx = – 10/(x² +3)²

============

5a)

^nP5 ÷ ^nC4 = 24

n!/(n-5)! ÷ n!/(n-4)!4! =24

n!/(n-5)! * (n-4)!4!/n! =24

(n-4)!4!/(n-5)!=24

(n-4)(n-5)!4!/(n-5)! = 24

n-4=1

n=4+1

n=5

b)PR= 5C3 (1/6)³ (5/6)^5-3

5!/(5-3)!3! (1/6)³ (5/6)²

5!/2!3! (1/6)³ (5/6)²

10 (1/216) (25/36)

=0.03215

Pr = 1-0.03215

=0.9678

==========

6) make a table containing

MARKS,TALLY,F & FX

UNDER F – 2,9,4,2,2,1

UNDER FX – 2,18,12,8,10,6

€F= 20

€FX = 56

6b) Mean = €fx / €f

= 56 / 20

= 2.8

==============

7)

Given

h=15.4t-4.9t

Velocity V=dh/dt =15.4-9.8t

At maximum height V=0

Therefore 15.4-9.8t=0

9.8t=15.4

t=15.4/9.8

t=1.6secs

Time to reach maximum height is 1.6secs

7b)

maximum h=15.4t-9.4t^2

15.4(1.6)-4.9(1.6)^2

22.64-12.544

=12.096

Max height = 12.1m

============

9a)X+6/(x+1)^2 = A/x+1 + B/(x+1)² + C/(x+1)³

X+6/ ~(x+1)³~ =A(x+1)² + B(x+1) + C / ~(x+1)³~

X+6 =A (x+1)² + B(x+1) + C

Let X+1=0 , X=-1

-1+6= A (-1+1)² + B(-1+1) +C

5= C

Therefore:- C=5

X+6= A(X2+2x+1) + Bx + B + C

X+6= Ax²+2Ax+A+Bx+B+C

comparing the coefficient of X²

A=0

Comparing the coefficient of X

1=2A+B

1=2(0)+B

B=1

x+6/(x+3)² = o/x+1 + 1/(x+1)² + 5(x+1)³

1/(x+1)² + 5/(x+1)³

============

10a)

3x^2+x-2 <= 0 3x^2+3x-2x-2 <= 0 3x(x+1) -2 (x+1) <= 0 (3x-2)(x+1) <= 0

3x-2 <= 0 or 8+1 <= 0

**Keep refreshing this page as update will be made in jiffy**

**Incoming Searches.**

*waec**gce**further mathematics quest**i**ons**waec questions for further mathematics*

*2019/2020**waec gce**further**mathematics*

*waec gce further mathematics p**a**st**questions download**waec further mathematics questions**gce**further mathematics questions 2019**waec further mathematics question**further mathematics questions for GCE*

If you need us to help you with updated questions and answers at the right time about ** WAEC GCE Further Mathematics Examination 2019**, kindly provide us your phone number and email address in the comment box below. Also feel free to ask any question pertaining to this guide.

What’s your take on this? We believe this article was interesting right, if yes, don’t hesitate using our share button below to inform – friends and relation via Facebook, twitter or Google+.

**CSN Team**

**Join Over 500,000+ Readers Online Now.**

**♦ Subscribe NOW to Latest GIST from CSN PORTAL in Your EMAIL ADDRESS**

**Copyright Warning:**

*Contents on this website may not be republished, reproduced, redistributed either in whole or in part without due permission or acknowledgement. All contents are protected by DMCA.*

**The content on this site is posted with good intentions. If you own this content & believe your copyright was violated or infringed, make sure you contact us at [[email protected]] to file a complaint and actions will be taken immediately.**### Most Recommended Links

**Tags**: 2019 WAEC GCE Further Mathematics Questions, 2019/2020 WAEC GCE Further Mathematics Questions, WAEC, WAEC 2019 GCE Further Mathematics, WAEC GCE Further Mathematics, WAEC GCE Further Mathematics Questions